Question

Find the value of ‘p’, if the following quadratic equation has equal roots [3]
4
2 − ( − 2) + 1 = 0

Answer 1

Step-by-step explanation:

x2+(p−3)x+p=0

Here, a=1,b=(p−3),c=p

Given that the roots are equal,

So, Discriminant =0⇒b2−4ac=0

D=(p−3)2−4(1)(p)=0

⇒p2+9−6p−4p=0

⇒p2−10p+9=0

⇒p2−9p−p+9=0

⇒p(p−9)−1(p−9)=0

⇒(p−9)(p−1)=0

⇒p−9=0 or p−1=0

Hence, p=9 or p=1