Question

.find the value of p if the following quadratic equation have equal roots ​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

6, -2

Step-by-step explanation:

condition of equal root is

D=0

D=

$\sqrt{b^{2} - 4ac}$

therefore,

((p-2)^2 -4(4)(1))^1/2 = 0

(p^2-4p+4 - 16)^1/2 =0

(p^2-4p-12) = 0

p^2- 6p +2p -12 = 0

p(p-6) + 2(p-6) =0

(p-6)(p+2)=0

p= 6, -2