Question

Find the value of 'p. if the following quadratic
equations have equal roots
x2-(P-3]x+p=0​

Answer 1

Answer:

p=1 or p=9

Step-by-step explanation:

x2 + (p – 3)x + p = 0

Here a = 1, b = p – 3, c = p

For real and equal roots

D = b2 – 4ac = 0

(p – 3)2 – 4 × 1 × p = 0p

p2 – 6p + 9 – 4p = 0

p2 – 10p + 9 = 0

⇒ p2 – p – 9p + 9 = 0

p (p – 1) – 9 (p – 1) = 0

⇒ (p – 1) (p – 9) = 0