Question

Find the value of p if the lines. 5x – 3y + 2 = 0 and 6x - py+ are
perpendicular to each other. Hence find the equation of a line passing through
(-2, -1) and parallel to 6x - py+ 7 = 0.
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Answer 1

Answer:

Step-by-step explanation:

5x-3y+2=0

By slope intercept form

Y=5x/3+2/3

m=5/3

6x-py+7=0

By slope untercepr form

Py=6x+7

Y=6x/p +7/p

m=6/p

Since the lines are perpendicular

Therefore m×m=-1

5/3×6/p=-1

30/3p=-1

30=-3p

P=30/-3

P=-10

Slope of 6x-py+7=0 is m=6/p=6/-10=-3/5

Since lines are parallel slopes are equal

Therefore m=-3/5 (-2,-1)

Y-y=m (x-x)

Y- (-1)=-3/5 (x-(-2))

Y+1=-3/5 (x+2)

5y+5=-3x-6

3x+5y+5+6=0

3x+5y+11=0

Answer 2

Step-by-step explanation:

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