Question

find the value of p if the number X, 2x+p, 3 x + 6 are 3 consecutive of an AP

Answer 1

HEYA!

GOOD EVENING!

x,2x+P ,3x+6 are in AP then

(x)+(3x+6) = 2*[2x+P]

i.e. 4x+6=4x+2P

i.e. 6=2 P

i.e. P=3.

Answer 2

Hey

Here is your answer,

All these terms are consecutive then the common difference between these numbers will be same .

a2 - a1 = a3 - a2
( 2x + p ) - (x) = (3x +6 ) - (2x + p)
2x + p - x = 3x + 6 - 2x - p
X + p = x + 6 - p
p = 6-p
p+p = 6
2p = 6
p = 6/2
p = 3

Hope it helps you!