Question

find the value of p if the pair of equations has no solution:
-x+py=1 and px-y=1​

Answer 1

Answer:

p = ±1

Step-by-step explanation:

It has no solution. So,

a_{1}/a_{2}  =  b_{1}/b_{2}  \neq  c_{1}/c_{2}

It Means

-1/p = p/-1

[cross multiplication]

p^{2}  = (-1)(-1)\\

p^{2}  = 1\\

p = \sqrt{1}\\

p = ±1

Answer 2

Answer:

here, A1=-1,B1= p , C1= -1

and ,

A2= p , B2= -1, C2= -1

we know that,

A1/A2=B1/B2≠C1/C2

-1/p=p/-1≠-1/-1

-1/p≠1/1

hence, p ≠ -1