find the value of P if the point A(0,2) is equidistant from (3,p) and(p,3)
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Using the distance formula,
√[(3-0)²+(p-2)²] = √[(p-0)²+(3-2)²]
Squaring both sides,
9+p²-4p+4=p²+1
4p=12
p=3
√[(3-0)²+(p-2)²] = √[(p-0)²+(3-2)²]
Squaring both sides,
9+p²-4p+4=p²+1
4p=12
p=3
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