Question

Find the value of p if the points a(p,2), b (3, - 4) and c(4,-5) are collinear

Answer 1

Answer:

p = -3

Step-by-step explanation:

Given:- x1 = p y1 = 2

x2 = 3 and y2 = -4

x3 = 4 y3 = -5

here it is given that the points are collinear,

so, we use the formula of area of triangle which is equal to 0.

because, the points are collinear.

now,

1/2 [ X1(y2-y3) + x2(y3-y1) + x3(y1-y2) ] = 0

, 1/2 { p[-4 -(-5)] + 3(-5-2) + 4[2-(-4)] } = 0

, 1/2 [ p(-4+5) + 3(-7) + 4(2+4) ] = 0

, 1/2 [ p(1) - 21 + 4(6) ] = 0

, 1/2 ( p-21+24 ) = 0

, p - 21 + 24 = 0×2

, p + 3 = 0

, p = -3

hence,

the value of 'p' is equal to -3.

I hope.... you have understood by this easy way to find out the Value of 'p'.

please.... mark in brainliest...