Question

find the value of p,if the quadratic equation p2x2-12x+p+7=0 has the root 3/2

Answer 1

Answer:

p = 2, -22/9

Step-by-step explanation:

p2x2 -12x +p+7 = 0, root given is 3/2

substituting the value of 3/2 in x, we get

p2(3/2)^2 -12(3/2) +p+7 = 0

9/4p^2 -18 +p+7 = 0

9/4p^2 +p -11 = 0

Using Discriminant method

b^2 -4ac

(1)^2 -4(9/4)(11)

1 + 99

= 100

Using Quadratic Formula,

p = (-b ± √b^2 -4ac)/2a

= (-1 + 10)/9/2   ; (-1 -10)/9/2

= 2(9)/9 ; 2(-11)/9

= 2 ; -22/9

Answer 2

Answer:

x=22/9,x=2

Step-by-step explanation:

• here is your answers