Question

Find the value of p, if the roots of 2x^2 - 6x +p=0 are real and equal.​

Answer 1

Step-by-step explanation:

Real & equal roots means ,

${b}^{2} - 4ac = 0$

comparing with standard equation,

a = 2, b = -6, c = p

$( - 6) ^{2} - 4(2 \times p) = 0 \\ 36 - 8p \: = 0 \\ 36 = 8p \\ p = 36 \div 8 \\ p \: = 9 \div 2 \\ p = 4.5 = 4 \times \frac{1}{2}$

Please mark branliest

Answer 2

Answer:

Well I guess you've already got the answer

Step-by-step explanation:

It is correct