Question

Find the value of 'p' if the roots of equation : px² - (2p-2)x+p = 0 has equal real roots​

Answer 1

Answer:

px2−8x+2p=0 

here, a=p,b=−8,c=2p

For equal roots b2−4ac=0

or, (−8)2−4(p)(2p)=0

or, 64−8p2=0

or, −8p2=−64

or, 8p2=64

or, p2=864=8

or, p=±8=±22

Answer 2

Answer:

Kya hua you are just ignore me