Question

find the value of P, if the stright lines 3x+7y-1=0 and 7x-py+3=0 are mutually perpendicular​

Answer 1

Answer:

$3x + 7y - 1 = 0 \\ 3x = 1 - 7y \\ x = 1 - 7y \div 3 \\ \\ \\ \\ 7x - py + 3 = 0 \\ 7x = py - 3 \\ x = py - 3 \div 7$