Math, asked by suddhasilsarkar, 4 months ago

Find the value of P if the value of x^4-3x^3-px-5 is equal to 23 when x=-2

Answers

Answered by AeshikaGupta
3

Answer:

x^4 - 3x^3 - px - 5 = 23

substituting value of x with -2,

(-2)^4 - 3*(-2)^3 - p*(-2) - 5 = 23

16 - 3*(-8) + 2p - 5 = 23

16 + 24 + 2p - 5 = 23

25 + 2p = 23

2p = 23 - 25

p = -2/2

p = -1

Step-by-step explanation:

hope it helps

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