Math, asked by shreyanshsen2009, 5 days ago

find the value of p if the value of x ⁴ -3x³-px-5 is equal to 23 when x is equal to -2.​

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Answered by VelvetRosee
2

Answer:

the value of p = -6

Step-by-step explanation:

given that :

we have to find the value of 'p' if the value of  (x⁴ -3x³-px-5)  is equal to 23 when x = -2.

let's equate it.

(x⁴ -3x³-px-5)  = 23

substitute value of x=-2 in above equation.

(-2)⁴ - 3(-2)³ - p(-2) -5 = 23

when the power is even , (-) becomes (+)

2⁴ - (3)(-2³) - p(-2) - 5 = 23

(2)(2)(2)(2) - (3)(-2)(-2)(-2) - p(-2) - 5 =  23

(4)(4) - (3)(4)(-2) + 2p - 5 = 23

16 +(3)(4)(2) + 2p - 5 = 23

16 + (12)(2) + 2p - 5 = 23

16 + 24 + 2p - 5 = 23

40 + 2p - 5 = 23

2p + 35 = 23

2p = 23 - 35

2p = -12

p = (-12)/2

p = -6

so  the value of 'p' if the value of (x⁴ -3x³-px-5) is equal to 23 when x is equal to -2.  is -6

Answered by somumalleswari
2

Answer:

the answer is 6

Step-by-step explanation:

I hope it helped you

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