Question

find the value of p if x-1 is a factor of polynomial 2x^3 + 2x^2 + x + p

Answer 1

Given that (x-1) is a factor of polynomial 2x^3 + 2x^2+x+p


so (x-1)(2x^3+2x^2+x+p) will be =0

(x-1)=0, x=1 ..

subsitute it in 2x^3+2x^2+x+p=0

2(-1)^3 + 2(-1)^2 + (-1) + p =0

2(-1) + 2(1) - 1 + p =0

-2 + 2 -1+p =0

-1 +p = 0

p = 1 ...so '1' is the answer

Answer 2

Answer:

p= -5

Step-by-step explanation:

Finding Zero :- x-1=0

x=0+1

x=1

P(x) =2x^3+2x^2+x+p

So, P(1) = 2(1)^3+2(1)^2+(1)+p = 0

2+2+1+p=0

5+p=0

p=0-5

p= -5