Question

Find the value of p if (X+1) is a factor of polynomial 2x cube-2x square+X+p​

Answer 1

Step-by-step explanation:

x + 1 = 0

x = - 1

2x³ - 2x²+ x + p

put the value of x

2(-1)³ - 2(-1)² +( -1) + p = 0

-2 -2 -1 + p =

-5 + p =0

p= 5 ans.

hope it helps you

Answer 2

Question: Find the value of p if (x + 1) is a factor of polynomial $2x^3-2x^2+x+p$.

Answer:

The value of p is 5.

Step-by-step explanation:

Factor Remainder Theorem - If p(x) is a polynomial and $a$ is any real number, then when p(x) is divided by x − $a$, the remainder is p($a$).

Step 1 of 1

To find the value of p.

Consider the given polynomial as follows:

$p(x)=2x^3-2x^2+x+p$ . . . . . (i)

It is given that (x + 1) is a factor of the polynomial $2x^3-2x^2+x+p$.

This means on dividing the given polynomial by (x + 1) leaves remainder 0.

By Factor remainder theorem,

$p(-1)=0$

Substitute the value -1 for $x$ in the polynomial (i) as follows:

$p(-1)=2(-1)^3-2(-1)^2+(-1)+p$

Simplify as follows:

$0=2(-1)-2(1)+(-1)+p$

$0=-2-2-1+p$

$0=-5+p$

$p=5$

Therefore, the value of p is 5.

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