find the value of 'p' if (x-1) is factor of 4x³+3x²-px-3
step-by-step please!
Answers
Answered by
1
g(x)=0
x-1=0
x=1
Putting X=1 in p(x)=4x³+3x²-px-3=0
p(1)=4(1)³+3(1)²-p×1-3=0
4+3-p-3=0
4-p=0
-p=-4
p=4.
Hence, the value of p=4.
Answered by
1
if x-1 is a factor then it means if we pit the value ‘1’ in place of x, the sum will be 0
This means
4*1^3+3*1^2-p*1-3=0
4+3-p-3=0
4-p=0
p=4
This means
4*1^3+3*1^2-p*1-3=0
4+3-p-3=0
4-p=0
p=4
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