Question

Find the value of p if x = 1 is solution of 2x
²– px + 5 = 0​

Answer 1

If $x = 1$ is the solution of $2x^2 - px + 5 = 0$ then it must satisfy the Equation.

Putting $x = 1$ in the Equation.

$2(1) ^{2} - p(1) + 5 = 0 \\ 2 - p + 5 = 0 \\ 7 - p = 0 \\ p = 7$

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Answer 2

Step-by-step explanation:

the value of x=1

given that

2[x]2 - px +5 =0

2[1]2 -p[1] +5 =0

2×1 -p[1] +5 =0

2 - p[1] +5 =0

2+5 -p[1] =0

7 -p[1] =0

7 -p×1 =0

7 -p =0

therefore -p = -7

Here,both LHS AND RHS SIGNS ARE CANCLE

SO,,P =7

THE VALUE OF P =7

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