Find the value of p if x-2 is factor of polynomial xcube-pxsqure+12
Answers
Answered by
1
Answer:
p = 5
Step-by-step explanation:
let us say p(x) = x³ - px²+12
If x -2 is factor of the polynomial equation then substituting x = 2 should in the equation should result in zero.
=> p(x=2) = 0
=> (2)³ - p(2)²+12 = 0
=> 4p = 20
=> p = 5.
Answered by
0
Answer:
Step-by-step explanation:
p=1
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