Question

Find the value of p if x3 – px + 10x2 – 6=0 for x = 1.

Answer 1

Answer:

Step-by-step explanation:

x³ - px + 10x² - 6 = 0

⇒ x³ + 10x² - px - 6 = 0

Now substituting " x = 1 " in the above equation ,we get

⇒ ( 1 )³ + 10 ( 1)² - p ( 1 ) - 6 = 0

⇒ 1 - 10 - p - 6 = 0

⇒ 1 - 16 - p = 0

⇒ - 15 - p = 0

⇒ p = - 15 is the answer.

Answer 2

• We have to evaluate the above expression by using the given data.

              Given data:- $x=1.$

              To find:- $x^{3} -px+10x^{2} -6=0.$

              Solution:-

• Here, we will use the below following steps to find a solution using the transposition method.

• Here we will use the transposition method.

• Transposition is one of the linear equations.

• To solve the transposition method we wi.ll Identify the variables and constants.

• Then we Simplify the equation in LHS and RHS.  

      Now put the value of x=1 in the given equation, we get

        $=>1^{3} -p(1)+10(1)^{2} -6=0\\=>1-p+10-6=0\\=>5-p=0\\=>-p=-5\\=>p=5$

     Hence we will get the value $p=5.$