Question

Find the value of p if x³-px+10x²-6=0 for x=1 ​

Answer 1

Answer:

substitute 1 in place of X

1 cube - p(1) + 10 (1) square - 6 = 0

1 - p + 10 - 6 = 0

11 - 6 = 0 + p

5 = p

Answer 2

x³-px+10x²-6 = 0 ---(x=1)

1³-p*1+10*1²-6=0

1-1p+10-6=0

1-1p+4=0

1p = 4+1 =0

1p =5

p=5/1 = 5

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Additional Information :-

To confirm your Ans

x³-px+10x²-6=0

1³-5*1+10*1²-6=0

1-5+10-6=0

-4+10-6=0

6-6=0

0=0

(Proved)