Question

Find the value of “p'if xyp = (3x + y)2 – (3x - y)2
.​

Answer 1

Answer:

p = 12

Step-by-step explanation:

(a + b)^2 = a^2 + 2*a*b + b^2

(a - b)^2 = a^2 - 2*a*b + b^2

xyp = (3x + y)^2 - (3x - y)^2

      = (3x)^2 + 2*3x*y + y^2 [(3x^2 - 2*3x*y + y^2)]                  

      = 9x^2 + 6xy + y^2 - [9x^2 - 6xy + y^2]

      = 9x^2 + 6xy + y^2 - 9x^2 + 6xy - y^2

      = 6xy + 6xy

xyp = 12xy

p = 12xy/xy

p = 12

Answer 2

Answer:

here,

xyp=(3x+y)^2-(3x-y)^2

by expanding

xyp=9x^+y^2+6xy-9x^-y^2+6xy

xyp=12xy

therefore,p=12

hope,it helps you.