Question

Find the value of p,ifthe straight line 3x+7y-1=0 and 7x-py+3=0 are mutually perpendicular

Answer 1

Answer:

your answer is-2/3 and here is the explanation

Step-by-step explanation:

Concept: Slope of general equation of line ax+by+c=0 is m=−  coefficient of y /coefficient of x  

Therefore,

The slope of line 2x+3y−3=0 is =−  2/3

and slope of line x+ky+7=0 is −  1/k

Now we know that two lines are perpendicular if their product of slopes is−1

⇒−  2/3×-- 1/k= =−  1

⇒k=−  2/3

MARK ME AS BRAINLIEST AND FOLLOW ME TO GET YOUR BEST ANSWERS  

LET ME KNOW HOW HELPFUL MY ANSWER WAS TO U.....

Answer 2

Answer:

• Step-by-step explanation:given: 3x+7y-1=0 , 7x-py+3=o                                    
•                    : a1.a2+b1.b2    
•   a1 =3 ,a2=7 ,b1=7, b2 =p  
•    3 x 7 + 7 x -p =0
•    21 - 7p =0
•   21 = 7p
•   p = 3