Question

find the value of p in (3p)^3x9^2×243^-5=1​

Answer 1

Hola mate! Here is your answer:-

Given:

$({3p}^{3})( {9}^{2} )( {243}^{ - 5)} = 1$

Solution:

$\frac{ {3p}^{3} \times {3}^{4} }{ {243}^{5} } = 1$

$\frac{ {3p}^{3} \times {3}^{4} }{ {3}^{ - 25} } = {3}^{0}$

${3p}^{3} = {3}^{0} \times {3}^{ - 25} upon {3}^{4}$

${3p}^{3} = {3}^{ - 29}$

${p}^{3} = \frac{ {3}^{ - 29} }{3}$

${p}^{3} = \frac{1}{ {3}^{30} }$

$p = \frac{1}{ {3}^{10} }$