Find the value of p in 5^p-4*2^p-5=5
note that p-4 and p-5 are the powers of 5 and 4 respectively!!!
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Step-by-step explanation:
Given P(1)=1,P(2)=2,P(3)=3,P(4)=5
Let f(x)=(P(x)−x)
f(1)=P(1)−1=1−1=0
f(2)=P(2)−2=2−2=0
f(3)=P(3)−3=3−3=0
∴f(x)=0,x=1,2,3
⇒f(x)=a(x−1)(x−2)(x−3)
P(x)=a(x−1)(x−2)(x−3)+x
Put x=4
5=a(3)(2)(1)+4
⇒a=
6
1
∴P(x)=
6
1
(x−1)(x−2)(x−3)+x
∴P(6)=
6
1
(5)(4)(3)+6=16
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