Question

Find the value of p in each case:
(a) (-3)^p+1 × (-3)^5= (-3)^7​

Answer 1

Answer: (-3)^p+1 × (-3)^5= (-3)^7

(-3)^(p+1+5)= (-3)^7

(-3)^(p+6)= (-3)^7

On comparing,

p+6 = 7

p = 1

Hope it helps!

Plz. Mark it as the Brainiest.

Answer 2

Answer:

p = 1

Step-by-step explanation:

${ - 3}^{p + 1} \times { - 3}^{5} = { - 3}^{7} \\ = > { - 3}^{p + 1 + 5} = { - 3}^{7} \\ = { - 3}^{p + 6} = { - 3}^{7} \\ on \: considering \: the \: powers \: \\ = > p + 6 = 7 \\ = > \fbox{p = 1}$

Please mark my answer as Brainliest!