Question

find the value of p in the equation x^2-2(1+3p)x+7(3+2p)=0​

Answer 1

Answer:

hope its helpful

Step-by-step explanation:

x^2-2x-6px+21+14p=0

if the eqvation has equal roots

discriminant=0

b^2+4ac=0

(2(1+3p))^2+4x1x(7(3+2p))=0

now we get a quadratic equation

9p^2-8p-20=0

p=2or -10/9

Answer 2

Answer:

p=2 or p=-10/9

Step-by-step explanation:

a=1, b=-2(1+3p) ,c=7(3+2p)

b^2-4ac=0

[-2(1+3P]^2-(4×1×7(3+2P)=0

4((1+3p)^2-(7(3+2p)=0

1+6p9p^2-(21+14p)=0

9p^2-8p-20=0

9p^2-18p+10p-20=0

p-2)(9p+10=0

p-2=0 ,9p+10=0

p=2 , p=-10/9