Math, asked by sathiyabamagovindan, 1 year ago

Find the value of p in the following 16-1\3(2pq+6)=0 when q=3

Answers

Answered by aimanwani

1

16-1/3 (2×p×3+6)=0
16-1/3 (6p+6)=0
47/3 (6p+6)=0
94p+94=0
94p=-94
p=-94/94
p=-1

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Answered by sajujency

0

Answer:

Hope it helps so

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