Question

Find the value of p in which the
x2-4x2-px+8=0
is exactly divisible by
(x-2)
​

Answer 1

$\underline{ \underline { \huge \red{\mathbb{ANSWER}}}}$

x² - 4x² - px + 8 = 0

(x - 2) is a factor of this...

so, put x = 2

➪ (2)² - 4 × (2)² - p × 2 + 8 = 0

➪ 4 - 4 × 4 - 2p + 8 = 0

➪ 4 - 16 - 2p + 8 = 0

➪ 2p = 12 - 16

➪ 2p = -4

➪ p = -4/2

➪ p = -2

so, value of p is -2

Answer 2

Answer:

ANSWER

x² - 4x² - px + 8 = 0

(x - 2) is a factor of this...

so, put x = 2

➪ (2)² - 4 × (2)² - p × 2 + 8 = 0

➪ 4 - 4 × 4 - 2p + 8 = 0

➪ 4 - 16 - 2p + 8 = 0

➪ 2p = 12 - 16

➪ 2p = -4

➪ p = -4/2

➪ p = -2

so, value of p is -2