Question

Find the value of p(o) and p(1) for p(x)=x2-2x+2

Answer 1

p(x)=x^2-2x+2
p(0)= (0)^2-2(0)+2
= 0-0+2
= 2
p(1)= (1)^2-2(1)+2
= 1-2+2
= 1
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