Question

Find the value of p(o) and p(1) for p(x)=x2-2x+2

Answer 1

Answer:

Given : p(0) ,p(1) for p(x)

${x}^{2} - 2x + 2$

Solution:

Put p(0) in x

$= {x }^{2} - 2x + 2$

$= {0}^{2} - 2(0) + 2$

$= 2$

Put p (1) in x

$= {x}^{2} - 2x + 2$

$= {1}^{2} - 2(1) + 2$

$= 1 - 2 + 2$

$= 1$

Step-by-step explanation:

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