Math, asked by sawankumardinesh1234, 1 month ago

Find the value of P(O), P(1) and P(2) for y2 - 2y + 1.​

Answers

Answered by twinkle385
9

Answer:

 {y}^{2}  - 2y + 1 \\  \: p(0 ) \:  =  {0}^{2}  - 2  \times 0 + 1 \\  = 1 \\  \\ \: p(1) =  {1}^{2}  - 2 \times 1 + 1 \\  = 1 - 2 + 1 \\  = 0 \\  \\ p(2) =  {2}^{2}  - 2  \times 2 + 1 \\  = 4 - 4 + 1 \\  = 1

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