Question

Find the value of P(O), P(1) and P(2) for y2 - 2y + 1.​

Answer 1

Answer:

${y}^{2} - 2y + 1 \\ \: p(0 ) \: = {0}^{2} - 2 \times 0 + 1 \\ = 1 \\ \\ \: p(1) = {1}^{2} - 2 \times 1 + 1 \\ = 1 - 2 + 1 \\ = 0 \\ \\ p(2) = {2}^{2} - 2 \times 2 + 1 \\ = 4 - 4 + 1 \\ = 1$

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