find the value of p of equation px2-14x+8
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A quadratic equation can be written in the form x^2+(alpha+beta)/ax+(alpha×beta)/a.(Where alpha and beta are the zeroes of the equation.
Therefore p=1.
The quadratic equipment is 1x^2+14/1x+8/1
Therefore p=1.
The quadratic equipment is 1x^2+14/1x+8/1
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