Question

find the value of P' of the following
quadratic equation has equal roots.
4x2 - (p-2)x+1=0​

Answer 1

Answer:

p=6

Step-by-step explanation:

a,a are roots

a^2=1/4

a+a=(p-2)/4

2a=(p-2)/4

a=(p-2)/8

(p-2)^2 /64 =1/4

(p-2)^2=64/4

p-2=sqrt (16)

p-2=4

p=6