Question

find the value of p of which the equation 2y²-py+1=0 has equal roots.​

Answer 1

Answer:

p=2√2

Step-by-step explanation:

2y²-py+1=0

a=2, b=p, c=1

Discriminant=0

b²-4ac=0

(p)²-4(2)(1)=0

p²-8=0

p²=8

p=√8

p=2√2

Therefore, the value of p is 2√2.