Question

find the value of p.
please tell me fast.................
it's urgent...... no spamming..... otherwise I will report......​

Answer 1

Step-by-step explanation:

Given that :-

abp=(3a+b)²-(3a-b)²

(since (a+b)²=a²+2ab+b²

(a-b)²=a²-2ab+b²)

here a=3a, b=b

=>abp=[(3a)²+2(3a)(b)+b²]-[(3a)²-2(3a)(b)+b²)]

=>abp=(9a²+6ab+b²)-(9a²-6ab+b²)

=>abp=9a²+6ab+b²-9a²+6ab-b²

=>abp=(9a²-9a²)+(6ab+6ab)+(b²-b²)

=>abp=0+12ab+0

=>abp=12ab

=>p=12ab/ab

(cancelling ab)

=>p=12

The value of p is 12

Answer 2

Answer:

p=12

Step-by-step explanation:

abp = (3a + b)² - (3a - b)²

abp = 9a² + b² + 6ab - (9a² + b² - 6ab)

abp = 9a² + b² + 6ab - 9a² - b² + 6ab

abp = 6ab + 6ab

abp = 12ab

p = 12