Math, asked by singhalok77, 2 months ago

Find the value of P-Q-13 .if P = 6x²-1 1x and Q= -3x² -12 +5x.​

Answers

Answered by krpalcham
1

Answer:

Step-by-step explanation:

P-Q-13

P=6X²-11X

Q=-3X²-12+5X

P-Q-13→6X²-11X-(-3X²-12+5X)-13

          =6X²-11X+3X²+12-5X-13

            =9X²-16X-1

SOLVING FOR X USING QUADRATIC EQUATION aX²+BX+C

X= (-B±√(B²-4AC))/2A

WE GET 5.4

Similar questions