Find the value of (p+q+R2) -10 pqr. When p = 2 , q = -1 , r = 2
Answers
Answered by
0
Step-by-step explanation:
r=2
p= 2
q= -1
(p+q+r2)+10
( 2+(-1)+2.2)+10
(2-1+4)+10
(6-1)+10
=5+10
= 15
Answered by
1
Answer:
The value of [ ( p + q + r2 ) - 10 p q r ] is 45.
Step-by-step explanation:
Value of p = 2
q = (-1)
r = 2
So,
( p + q + r2 ) - 10 p q r
[ 2 + (-1) + 2 × 2 ] - 10 × 2 × (-1) × 2
[ 2 - 1 + 4 ] - 10 × 2 × (-1) × 2
[ 2 + 3 ] - 10 × 2 × (-1) × 2
[ 5 ] - 10 × 2 × (-1) × 2
5 - 10 × (-2) × 2
5 - 10 × (-4)
5 + 40
45
The value of [ ( p + q + r2 ) - 10 p q r ] is 45.
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