Math, asked by gita67443, 8 months ago

Find the value of (p+q+R2) -10 pqr. When p = 2 , q = -1 , r = 2

Answers

Answered by srikrishna36
0

Step-by-step explanation:

r=2

p= 2

q= -1

(p+q+r2)+10

( 2+(-1)+2.2)+10

(2-1+4)+10

(6-1)+10

=5+10

= 15

Answered by sgadiya44
1

Answer:

The value of [ ( p + q + r2 ) - 10 p q r ] is 45.

Step-by-step explanation:

Value of p = 2

q = (-1)

r = 2

So,

( p + q + r2 ) - 10 p q r

[ 2 + (-1) + 2 × 2 ] - 10 × 2 × (-1) × 2

[ 2 - 1 + 4 ] - 10 × 2 × (-1) × 2

[ 2 + 3 ] - 10 × 2 × (-1) × 2

[ 5 ] - 10 × 2 × (-1) × 2

5 - 10 × (-2) × 2

5 - 10 × (-4)

5 + 40

45

The value of [ ( p + q + r2 ) - 10 p q r ] is 45.

HOPE THIS WILL HELP YOU!

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