Math, asked by mohitkhanwale9012, 1 year ago

Find the value of p so that 2y-1 be a factor of 8y^4-16y^2+4y^3+p+10y

Answers

Answered by mahi2000
1
the value of p will be-5
Answered by Rhebksnwn
1

2y=1

y=1/2 p(1/2) =8(1/2)^4 -16(1/2) ^2+4(1/2) ^3+p+10(1/2) 1/2-2+1/2+p+5 1+1+p 2+p p=-2

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