Find the value of p so that points with coordinates (3,5),(p,6)& (1/2,15/2) are collinear
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Area = 0
3(6-15/2) + p(15/2-5) + 1/2(5-6) = 0
3(12-15÷2) + p(15-10÷2) + 1/2(-1) =0
3(-3/2) + p(5/2) - 1/2 = 0
-9/2 + 5p÷2 - 1/2 = 0
-10/2 = -5p/2
2=P
I'm not sure about this answer...
3(6-15/2) + p(15/2-5) + 1/2(5-6) = 0
3(12-15÷2) + p(15-10÷2) + 1/2(-1) =0
3(-3/2) + p(5/2) - 1/2 = 0
-9/2 + 5p÷2 - 1/2 = 0
-10/2 = -5p/2
2=P
I'm not sure about this answer...
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