Find the value of p so that quadratic equation px(x-3)+9=0 has two equal roots ?
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discriminate will become 0 while roots r equal
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px(x-3)+9=0
=)px^-3px+9=0
b^-4ac=0
=)(-3p)^-4p9=0
=)9p^-36=0
=)9p^=36
=)p^=4
=)p=2
=)px^-3px+9=0
b^-4ac=0
=)(-3p)^-4p9=0
=)9p^-36=0
=)9p^=36
=)p^=4
=)p=2
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