Question

find the value of p so that the equation equation have real and equal root (p-12)x square +2(p-12)x+2
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Answer 1

Answer :

(P -12)x² +2( P -12) x + 2 =0 have two real and equal roots so,

D = b² -4ac =0

here,

b = 2( P -12)

a = (P -12)

c = 2

now,

D = {2(P -12)}² -4.2(P -12) =0

4{ (P -12)² -2( P -12) } =0

(P -12)² -2(P -12)=0

(P -12){ P -12 -2} = 0

(P -12)( P -14) =0

P = 12, 14

hence value of P = 12, 14

hope this will help you