find the value of 'p' so that the point [3,p] lies on the lines 2x-3y=5 ??????
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(3,p) lies on the line 2x-3y-5=0 it means (3,p) is a solution of this line
so 2x-3y-5=0
2x-3y=5
2*3-3p=5
6-5=3p
1/3=p
now coordinates of the point where line cut x axis
on x axis every point is of the form(x,0)
so 2x-3y=5
2x-3*0=5
2x=5
x=5/2
so 2x-3y-5=0
2x-3y=5
2*3-3p=5
6-5=3p
1/3=p
now coordinates of the point where line cut x axis
on x axis every point is of the form(x,0)
so 2x-3y=5
2x-3*0=5
2x=5
x=5/2
fardeenfazal12345:
but this is wrong
x = 2/5
kk
i have done that sum and i got that answer
ok....
my collage proffesor told that is right answer that x=2/5
oh .
then your answer is correct
yes obivously
kkk
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