Question

Find the value of ‘p’ , so that the quadratic equation ( − 3) + 9 = 0 has equal roots.

Answer 1

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-3+9=0

0=3÷9=3

p=3

Answer 2

Answer:

Px(x-3) + 9 = 0

px2-3px+9=0

a=p , b=-3p , c=9

b2-4ac= (-3p)2-4(p)(9)

=9p2-36p

for having equal roots  

b2-4ac = 9p2-36p = 0

9p2-36p = 0

9p(p-4) = 0

9p=0 (or) p-4=0

p=0(rejected) or p=4