Find the value of p so that the quadratic equation px(x – 3) + 9 = 0 has two equal roots
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1
Answer:
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Step-by-step explanation:
Px(x-3) + 9 = 0
px2-3px+9=0
a=p , b=-3p , c=9
b2-4ac= (-3p)2-4(p)(9)
=9p2-36p
for having equal roots
b2-4ac = 9p2-36p = 0
9p2-36p = 0
9p(p-4) = 0
9p=0 (or) p-4=0
p=0(rejected) or p=4
Answered by
1
Answer:
px(x-3)+9=0
px²-3px+9=0
given that two roots are equal
if b2-4ac = 0 then the roots are equal
a= p ,b=-3p, c= 9
b²-4ac= 0
(-3p)²-4(p)(9)=0
9p²-36p= 0
9(p²-4p)=0
p²-4p=0
p(p-4)=0
p=0, 4
p= 4
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