find the value of p so that the quadratic equationp(x)(x-3)+9=0 has two equal roots
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pxsq - 3px +9 =0
pxsq -9px +3px +9=0
9(px-px)+3(px+3 )=0
px = 3or 9 i think
pxsq -9px +3px +9=0
9(px-px)+3(px+3 )=0
px = 3or 9 i think
Answered by
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(x)(x-3)+9=0
x²-3x+9=0
a=1
b=-3
c=9
d=b²-4ac
d=-3²-4(1)(9)
d=9-36
d=-27
x=-b²-√d/2a
x=9-5.1/2
x=4
sorry its incomplete
x²-3x+9=0
a=1
b=-3
c=9
d=b²-4ac
d=-3²-4(1)(9)
d=9-36
d=-27
x=-b²-√d/2a
x=9-5.1/2
x=4
sorry its incomplete
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