Math, asked by sureshashwathi8, 2 months ago

find the value of p so that x² + 5xp + 16 = 0 has real and equal root

Answers

Answered by Ishita6006

1

-8/5 k 8/5

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Answered by gopika85

0

Answer:

x2+5xp+16=0

Step-by-step explanation:

16

-3 ^ +8

5

x2-3x+8p+16=0 x(x-3)-8(p-2)

x=3, 8 & p = 2

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