Question

find the value of p such that quadratic equation x^2-(p+6)x+2(2p-1)=0​

Answer 1

Step-by-step explanation:

please mark Brainliest

and follow me

Answer 2

Step-by-step explanation:

Answer:

Equation : x² - (p + 6)x + 2(2p - 1) = 0

a = 1

b = - (p + 6)

c = 2(2p - 1)

$\underline{\bigstar\:\textsf{According to the given Question :}}$

$:\implies\sf Sum \:of \:Roots = \dfrac{1}{2} \times Product \:of \:Roots\\\\\\:\implies\sf \dfrac{ -b}{a} = \dfrac{1}{2} \times \dfrac{c}{a}\\\\\\:\implies\sf - b = \dfrac{1}{2} \times c\\\\\\:\implies\sf -[-(p+6)]= \dfrac{1}{2} \times 2(2p-1)\\\\\\:\implies\sf p + 6 = 2p - 1\\\\\\:\implies\sf 6 + 1 = 2p - p\\\\\\:\implies\underline{\boxed{\sf p = 7}}$

⠀

$\therefore\:\underline{\textsf{Therefore, required value of p is \textbf{7}}}.$