Question

find the value of p such that quadratic equation x^2-(p+6)x+2(2p-1)=0 has sum of the roots as half of their product.​

Answer 1

Answer:

p=7

Step-by-step explanation:

let the roots be ā and ß

ā+ß= -b/a= -(-p+6)=p+6

āß= c/a=2 (2p-1)

ā+ß=āß/2

p+6=2p-1

-p= -7

p=7