Find the value of p such that (x - 1) is the factor of the polynomial x3+ 10x2 + px.
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Hii friend,
(X-1) is a factor of the polynomial X³+10X²+PX.
X-1 = 0
X = 1
P(X) = X³+10X²+PX.
P(1) = (1)³ + 10 × (1)² + P × 1
=> 1 + 10 + P = 0
=> P +11 = 0
=> P = -11.
HOPE IT WILL HELP YOU.... :-)
(X-1) is a factor of the polynomial X³+10X²+PX.
X-1 = 0
X = 1
P(X) = X³+10X²+PX.
P(1) = (1)³ + 10 × (1)² + P × 1
=> 1 + 10 + P = 0
=> P +11 = 0
=> P = -11.
HOPE IT WILL HELP YOU.... :-)
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